The principle is the same for light as well as electricity which are both electromagnetic waves travelling at a constant speed, regardless of the frequency or wave length but depending on the medium through which it is travelling. In vacum this speed is 299792458 m/s. The speed of any electromagnetic wave cannot change regardless of the frequency, else you will violate Einstein's theory of relativity. So what happens to light when it travels in one medium with imperfections, it changes direction, rather than changing speed. In an optical fibre this will cause optical reflections. These reflections are fully explained by
Fresnel's equations. These equations are furhter based on
interface conditions for electromagnetic fields and
maxwell's equations. When electricity passes through circuits having differing impedance it is exactly like light passing between two mediums with different refractive index. In case of electricity, the equivalent is impedance. But this phenomena even for electical signals are called reflections because they are exactly like what happens with light.
A perfect optical cable is one that has no imperfections to reflect light inside the cable. A perfect electrical cable is one which has zero resistance, zero capacitance and zero inductance. None of which is possible in real world.
When you are passing electricity through a wire, the wire is a series of infinite inductors and resistors in series and infinite capacitors in parallel. When the amp passes signal, it charges the first capacitor, then the second and so on till it reaches the end. If the circuit is open, the last capacitor charges with voltage more than the rest of the line capacitance. But the last capacitor is connected to the previous capacitor, so it charges the previous capacitor and so on and a positive wave travels back to the amp as a positive reflection wave. If the wire is shorted at the end, the last capacitor cannot charge. But it is has another capacitor before it, so it will discharge that. This discharging of capacitors then travels back to the source (at the speed of EM propagation) as a negative voltage reverse wave that cancels out the forward positive wave.
Somewhere between open and short is a nice medium value of impedance which doesn't allow overcharging or undercharging. Thus leaving no change in voltage to propagate back along the transmission line. That terminating impedance just happens to be the characteristic impedance of the transmission line, which is determined by the distributed capacitance and inductance of the wire, the speaker and the amp output, pcb trace, transformer connected to amp output, etc.
This is where I'm not clear. I think amps are designed for specific impedance of speaker (4 ohms or 8ohms generally) plus some impedance of the speaker wires. Or they are designed with the expectation that the speaker wire will have infinitesimally small impedance.