# Line slope calculator 5x+y=40

**Straight line given by points A[6; 10] and B[7; 5]**

## Calculation:

**Slope-intercept form of line:**y = -5x+40

**Canonical form of the line equation:**5x+y-40 = 0

**Parametric form of the line equation:**

x = t+6

y = -5t+10 ; t ∈ R

**Slope:**m = -5

**Slope angle of line: φ =**-78°41'24″ = -1.3734 rad

**X intercept:**x

_{0}= 8

**Y intercept:**y

_{0}= q = 40

**Distance line from the origin:**d

_{0}= 7.8446

**The length of the segment AB: |AB| =**5.099

**Vector: AB =**(1; -5)

**Normal vector: n =**(5; 1)

**Midpoint of the segment AB: M =**[6.5; 7.5]

**Perpendicular Bisector equation:**x-5y+31 = 0

**Vector OA = (6; 10) ; |OA| = 11.6619**

**Vector OB = (7; 5) ; |OB| = 8.6023**

**Scalar product OA .OB = 92**

**Angle ∠ AOB = 23°29'55″ = 0.4101 rad**