# Line slope calculator 8x-9y=8

**Straight line given by points A[1; 0] and B[10; 8]**

## Calculation:

**Slope-intercept form of line:**y = 0.8889x-0.8889

**Canonical form of the line equation:**8x-9y-8 = 0

**Parametric form of the line equation:**

x = 9t+1

y = 8t ; t ∈ R

**Slope:**m = 0.8889

**Slope angle of line: φ =**41°38'1″ = 0.7266 rad

**X intercept:**x

_{0}= 1

**Y intercept:**y

_{0}= q = -0.8889

**Distance line from the origin:**d

_{0}= 0.6644

**The length of the segment AB: |AB| =**12.0416

**Vector: AB =**(9; 8)

**Normal vector: n =**(8; -9)

**Midpoint of the segment AB: M =**[5.5; 4]

**Perpendicular Bisector equation:**9x+8y-81.5 = 0

**Vector OA = (1; 0) ; |OA| = 1**

**Vector OB = (10; 8) ; |OB| = 12.8062**

**Scalar product OA .OB = 10**

**Angle ∠ AOB = 38°39'35″ = 0.6747 rad**