# Line slope calculator 5x+y=46

**Straight line given by points A[8; 6] and B[9; 1]**

## Calculation:

**Slope-intercept form of line:**y = -5x+46

**Canonical form of the line equation:**5x+y-46 = 0

**Parametric form of the line equation:**

x = t+8

y = -5t+6 ; t ∈ R

**Slope:**m = -5

**Slope angle of line: φ =**-78°41'24″ = -1.3734 rad

**X intercept:**x

_{0}= 9.2

**Y intercept:**y

_{0}= q = 46

**Distance line from the origin:**d

_{0}= 9.0213

**The length of the segment AB: |AB| =**5.099

**Vector: AB =**(1; -5)

**Normal vector: n =**(5; 1)

**Midpoint of the segment AB: M =**[8.5; 3.5]

**Perpendicular Bisector equation:**x-5y+9 = 0

**Vector OA = (8; 6) ; |OA| = 10**

**Vector OB = (9; 1) ; |OB| = 9.0554**

**Scalar product OA .OB = 78**

**Angle ∠ AOB = 30°31'47″ = 0.5328 rad**