# Line slope calculator 3x+4y=15

**Straight line given by points A[1; 3] and B[5; 0]**

## Calculation:

**Slope-intercept form of line:**y = -0.75x+3.75

**Canonical form of the line equation:**3x+4y-15 = 0

**Parametric form of the line equation:**

x = 4t+1

y = -3t+3 ; t ∈ R

**Slope:**m = -0.75

**Slope angle of line: φ =**-36°52'12″ = -0.6435 rad

**X intercept:**x

_{0}= 5

**Y intercept:**y

_{0}= q = 3.75

**Distance line from the origin:**d

_{0}= 3

**The length of the segment AB: |AB| =**5

**Vector: AB =**(4; -3)

**Normal vector: n =**(3; 4)

**Midpoint of the segment AB: M =**[3; 1.5]

**Perpendicular Bisector equation:**4x-3y-7.5 = 0

**Vector OA = (1; 3) ; |OA| = 3.1623**

**Vector OB = (5; 0) ; |OB| = 5**

**Scalar product OA .OB = 5**

**Angle ∠ AOB = 71°33'54″ = 1.249 rad**