# Line slope calculator 5x+2y=12

**Straight line given by points A[0; 6] and B[2; 1]**

## Calculation:

**Slope-intercept form of line:**y = -2.5x+6

**Canonical form of the line equation:**5x+2y-12 = 0

**Parametric form of the line equation:**

x = 2t

y = -5t+6 ; t ∈ R

**Slope:**m = -2.5

**Slope angle of line: φ =**-68°11'55″ = -1.1903 rad

**X intercept:**x

_{0}= 2.4

**Y intercept:**y

_{0}= q = 6

**Distance line from the origin:**d

_{0}= 2.2283

**The length of the segment AB: |AB| =**5.3852

**Vector: AB =**(2; -5)

**Normal vector: n =**(5; 2)

**Midpoint of the segment AB: M =**[1; 3.5]

**Perpendicular Bisector equation:**2x-5y+15.5 = 0

**Vector OA = (0; 6) ; |OA| = 6**

**Vector OB = (2; 1) ; |OB| = 2.2361**

**Scalar product OA .OB = 6**

**Angle ∠ AOB = 63°26'6″ = 1.1071 rad**